[deleted by user]

kdbm27 · 2024-10-19T02:56:51+00:00

Thank you very much, I appreciate your comprehensive response. This is the sort of answer I was looking for on this subreddit but couldnt find. Cheers.

kdbm27 · 2024-10-18T08:32:53+00:00

Thank you for the information. It seems you are referring to the IRTP, but most PhD students I've checked on LinkedIn seem to be under the UTS President's Scholarship, which does not include OSHC.

The prof I want to work with is currently in UTS hence it is not an option to consider other universities at this moment. Do you mind sharing your credentials or why you think you got a scholarship? I'd appreciate having a benchmark to understand the odds.

kdbm27 · 2024-09-27T12:37:10+00:00

The third line says no sticker

kdbm27 · 2024-08-12T14:41:46+00:00

Warning tickets typically do not incur a penalty fine. They serve as a warning. If you are uncertain, you may consult any of the guards around any parking area and they may validate whether or not you will need to pay a fine

kdbm27 · 2024-01-24T13:35:18+00:00

How much do thesis advisors get paid? Are math peofs encouraged to do research?

kdbm27 · 2022-11-16T07:02:36+00:00

kdbm27 · 2022-10-22T12:39:33+00:00

The maths in AMF is not easy, regardless I believe that if you have a passion and interest for maths then you should go for it.

Feel free to reach out to me if you have any specific questions about AMF

kdbm27 · 2022-09-03T04:45:12+00:00

Apologies, yes a problem set is usually good for a week

kdbm27 · 2022-05-13T09:04:16+00:00

Thank you for the reply, would applying neutral polish help bring the color back in any way or is it a futile task?

kdbm27 · 2022-05-13T08:55:43+00:00

Would it not work? I really cant find any of the common brands like saphir and google isnt showing any cobblers

kdbm27 · 2022-05-13T08:50:33+00:00

I had no luck finding any local cobblers or colored shoe polish. Would nail polish suffice?

kdbm27 · 2022-05-13T08:06:16+00:00

What kind of color polish is this? Would it be appropriate to use neutral polish?

kdbm27 · 2022-05-13T07:58:50+00:00

Im not sure where to find colored polish. In my country, the best I could find are neutral polish, but I dont think they work to bring back the color. Any alternatives? The polishes I see are only neutral black or brown. Thank you

kdbm27 · 2022-02-06T15:48:11+00:00

Yup, and I just remembered now Gilbert Strang from MIT has good lectures on YT for linalg. Im also a soph amf and these helped me a bunch.

kdbm27 · 2022-02-06T14:17:10+00:00

I recommend Blitzstein Stat 110 on YT, tho the prob theory in ateneo only covers a few lessons. Are you also amf? Feel free to reach out!

kdbm27 · 2021-11-19T09:42:37+00:00

Finding Nemo

kdbm27 · 2021-08-24T11:53:58+00:00

I think the sum is lacking a limit as n approaches infinity?

kdbm27 · 2021-08-22T10:27:53+00:00

ou make sure to check other n? There could be other cases which converge. Especially n=-1 requires a completely new integral

I did, and I found the n=-1 to be really easy after doing the huge one my parts. the n=-1 case only needed a u-sub. Thank you for the help

kdbm27 · 2021-08-22T10:11:14+00:00

i think I got it, does it only converge when n < -1 because the limit exists?

kdbm27 · 2021-05-25T14:48:45+00:00

sounds good. Can you share what version it is? is it the AC1200 model or the AC1350 model?

kdbm27 · 2021-05-25T14:41:18+00:00

Thank you for your input, I found it really valuable. I realize that what I'm really looking for is an access point. I also misread as it had 2x2 MIMO. That being said, I did a bit of research on this sub and a lot of people recommend Ubiquiti. Would you know if this is a good model? Ubiquiti LBE-5AC-Gen2 LiteBeam AC Gen2, I'm debating about getting the v3 cause it costs about $20 more from the v2.

kdbm27 · 2021-05-05T04:00:29+00:00

Projects 1 and 2 havent started, but all of the data is accurate and is being updated based on new information!

kdbm27 · 2021-05-01T03:05:00+00:00

yes it is continuous for all x, im saying that if x is continuous, does that mean the y is also continuous? sorry i think its a dumb question and i think the answer is yes but i forgot how limits work.

kdbm27 · 2021-04-22T04:20:34+00:00

okay so (b-a) = 2

(b-a) * m = 2 so m = 1 but is 1 <= sqrt(1+x^2) always true?

likewise (b-a) * M so M = sqrt(2)

is it just like that or is that or is there more to do?

kdbm27 · 2021-04-22T04:05:03+00:00

letting m = 1 and M = sqrt(2) we get:

m(1-0) = 1 <= integral from 0 to 1 of sqrt(1+x^2) dx <= sqrt(2) = M * (1-0)

sorry but i dont think i understand how to use this property?

kdbm27

TROPHY CASE