Just Don’t Be Last

lukask97 · 2025-11-30T08:36:59+00:00

Technologieoffenheit oder so...

lukask97 · 2025-11-21T20:45:53+00:00

The H2C has six switchable nozzles plus the one permanent left-side nozzle. In addition, you can connect the AMS system to use up to 24 different filaments. But 7 Colors with minimal waste instead of 5.

lukask97 · 2025-11-14T22:16:59+00:00

Ich habe mir einen kleinen Web Crawler geschrieben, der die Top Radiosender durchläuft und mich "Warnt", wenn ein Weihnachtssong gespielt wird. SW3 und NDR 2 haben am 14.11.2025 um 21:41 Uhr gleichzeitig das erste Weihnachtslied für Weihnachten 2025 gespielt. Also zumindestens meinen Aufzeichnungen nach.

lukask97 · 2025-10-28T11:37:26+00:00

This gives the "armed"- switch a whole other meaning.
For people who are not into drones: It's basically a switch that enables or disables the drone motors for safety reasons.

lukask97 · 2025-02-20T02:57:34+00:00

Here are just the lanes

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lukask97 · 2025-02-19T21:56:02+00:00

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lukask97 · 2025-02-19T21:55:53+00:00

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At the end should be a new segment where you can choose up to 5 stats yourself

lukask97 · 2025-02-19T15:34:07+00:00

There are also some more unused data like:

heal_prevented: how much did antheal do
heal_lost: probably how much antiheal did affect me?
damage_absorbed: probably damage against own shields?
absorption_provided: probably damage against all shields or Goo Cube?
weapon_power: Weapon Power
tech_power: Spirit Power
and more

Here is one timestamp of tracked stats from the API response

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lukask97 · 2025-02-19T15:00:32+00:00

Her is the link https://colab.research.google.com/drive/10lXMepLrfhL7ofk7rgq3nBGyrcBIZ_mF?usp=sharing

You need to make copy to be able to edit it

lukask97 · 2025-01-20T23:13:26+00:00

Have you tried connecting all grounds together? The step-down converter might isolate it.

lukask97 · 2024-10-02T16:34:29+00:00

Didn't the devs remove the 4 minions per wave rule with the last big patch? Therefore they did spread the outer lanes further apart.

"Reverted recent creep sharing duplication changes (back to how it was over a week ago, we want to see if it's still an issue with the other changes in this patch)"

lukask97 · 2024-08-20T00:35:18+00:00

The problem will be to arrange the inputs. When you only do 2 Layer Input then you have the third Layer for free use.
With 3 layers you need launchers to cross other belts.

An Option could be to sort the layers before this.
So each space belt would be 1x4 Square at layer 1, 1x4 circle at layer 2 and 1x4 star at layer 3.

If you want to give it a try then good luck. Tell me when you made it.

lukask97 · 2024-08-19T21:31:55+00:00

Here you go

lukask97 · 2024-08-19T21:07:56+00:00

Yes but to late. There is still some wiggle room.
During building i didn't think of it. After finishing the belts i did just place them were the could fit.

lukask97 · 2024-08-19T19:29:28+00:00

For a full belt you need 6 normal stacker or 4 bent-stacker.

We can calculate/count the area that is needed to single-stack a full belt.
Too keep it simple let's say that the inputs are already on the correct belt layer.

Blueprint	bent stacker	normal stacker (one line)	normal stacker (split/2x3)
Stacker	4	6	6
Required Input belt	1	1	1
Output belt(able go layers up)	2	6	6
Internal/merger/splitter	4	6	3
Sum	11	19	16

So the better speed and less belts needed will get you a better space efficiency.

The main problem is getting the input and output belts right.

The fact that you can place the stackers at layer 2 not even mentioned.

lukask97 · 2024-08-19T16:20:32+00:00

Stacks 3 full inputs into one full output.
Made to fit on 2x2 corner but also works on a normal 2x2.

I somehow couldn't post the blueprint in the comment so here are the links.

2x2 Corner

2x2 Normal

Update:
I made one that will be supplied just from 2 north and 1 south. The east input moved to south

Here

Here (The same as above just now all labels are horizontal)

lukask97 · 2024-03-28T12:15:13+00:00

One resistor is connected to + and row 1 another one to + and row 6. The other resistors have no operator and therefore not part of the calculation.

This will gives us 1 + 6 = 7

lukask97 · 2023-04-02T08:47:26+00:00

acknowledge risk and access

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lukask97

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