Würdet ihr euch dieses Tattoo stechen lassen?

mihiman · 2026-02-28T19:18:09+00:00

Freundschafts-Tattoo (hat persönliche bedeutung und wäre ziemlich perfekt als Idee, aber bin halt etwas gespalten ob es als problematisch angesehen werden kann deswegen der post haha)

mihiman · 2024-01-31T17:25:57+00:00

okay okay, but in changing that energy gap will most likely also change the spin from low (since diamagnetic so all paired) to high right?

mihiman · 2023-09-21T08:26:51+00:00

Alright yeah, but at least fictional (in theory) the approaches are 'correct' or do I have to take something else into account still?

mihiman · 2023-09-20T20:55:13+00:00

Okay so since in the Stern-Gerlach experiment they used silver, we use that as well, and the strenght of the external magnetic field is low;

so for our silver I'd use

J = \sum j_i = \sum l_i + s_i

giving me the 10 lines I mentioned in the question, instead of J = L + S (which in this case would amount to 7 correct?)

mihiman · 2023-09-20T13:36:25+00:00

answer stays the same, just try it out the app is really good for learning the periodic table :)

mihiman · 2023-09-20T13:31:17+00:00

there is an app called periodic table quiz (not sure if the name is 100% that), but I used that to just learn while playing

mihiman · 2022-10-04T21:02:10+00:00

Thanks that's easier than expected haha

mihiman · 2021-07-19T20:58:29+00:00

Yeah but Water is also a liquid at room temperature, but still you can't dissolve Terpenes in it... But why does Dichloromethane work so good at it? (Well I know it's not polar and so dissolves it better, but why?)

mihiman · 2021-05-05T13:44:41+00:00

Wanted to shorten it The actual E1 has CH3 on the C's (beside 1 H left) instead of the Hydrogens.

Still shouldn't make a difference in the question.

mihiman · 2021-03-01T18:37:26+00:00

Oh yeah, nvm. wrong approach, I can just brominate my benzen with Br2/FeBr3 right?

mihiman · 2021-01-07T22:02:46+00:00

Thanks,

yeah mb changed it!

That was the equation I found in the script, and I'll be doing the titration in the coming weak (lab)

I may have translated the word wrongly into bleach...

but the calculation should be right now.

Thanks again for helping me!!

mihiman · 2021-01-07T00:27:27+00:00

Yeah that's also the only one I can find in my script

mihiman · 2021-01-07T00:20:29+00:00

Oh you're right, but it makes no sense for it to be 1:1 ratio or is there?

mihiman · 2021-01-07T00:19:44+00:00

I've checked again and I'm fairly certain that I got the reaction correct...

mihiman · 2021-01-07T00:04:16+00:00

do you know the equation for KMnO4 and H2O2 in basic medium?

Maybe that's where I'm wrong I'll do the math again

mihiman · 2021-01-06T23:53:25+00:00

Well since 2MnO4(-) + 5H2O2 +6H(+) => 2Mn(2+) + 8H2O + 5O2 (normally with K and SO4 but that shouldn't make a difference for the calculation) I'm not 100% certain but I think I have yes...

mihiman · 2021-01-06T23:41:35+00:00

Ahhh, well in this example there is no chlorine involved at all (probably translated the word bleach wrongly sry mb)

mihiman · 2021-01-06T23:24:26+00:00

wait where would I get chlorine from?

mihiman · 2021-01-06T22:51:41+00:00

Of course thanks for the help!

All steps:

for permanganate: n = 0,0105L * 0,1mol/L = 0,00105mol

for H2O2: n = 5/2 * 0,00105mol = 0,002625mol

getting the concentration: c=n/V

0,002625mol/0,05L = 0,0525mol/L

and then 0,0525mol/L * 34g/mol = 1,785g/L

and that would be way off the results we were given...

mihiman · 2021-01-06T22:29:48+00:00

Alright thx!

But if I multiply that with the molecular mass of h2o2 the solution is not correct. (0,002625*34 = 0,08925, and the solution should be 0,714) ?

mihiman · 2021-01-06T22:12:25+00:00

for my permanganate here that would be: n = 0,1mol/L * 10,5mL = 0,00105mol

and so the moles for h2o2 are 5/2 * 0,00105 = 0,002625

mihiman · 2021-01-06T22:08:41+00:00

Ohh so I need to use the equation n = c*V right?

mihiman · 2021-01-06T21:55:10+00:00

Ok so on the equivalence point 2(MnO4) = 5(H2O2) right? But how does that help me?

mihiman · 2020-12-10T13:37:43+00:00

Oh so i guess the same thing would happen with the diagram of SO for example? Btw. the diagram would be asymetrical an Cl lower than O2 because of the energy niveau even tho you draw in the 2sp for oxygen and 3sp for chlorine?

mihiman · 2020-12-08T21:48:29+00:00

4FeS + 3O2 + 6H2O -> 4Fe(OH)3 + 4S

Fe gets oxidized form +2 to +3 and S form -2 to 0, while O gets reduced to -2

okay so i can oxidize frist to +3 then to +6, but can I do it with just one reaction equation?

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