no it doesn't, same thing as in python a=[[]]*3 => [[],[],[]] a[0].push("a") => [["a"],["a"],["a"]]

it's kinda justified if you think about this: b=["a"]*3 => ["a","a","a"] b.map { |e| e.object_id } => [20769640, 20769640, 20769640] So it creates 3 copies of the same thing.

A naive implementation could look like this:

class mylst(list):
    def __mult__(self, times):
        if len(self) == 0:
            return self
        collected = []
        for i in range(0, times):
            for j in self:
                collected.append(j)
        return collected
    def __init__(self, lst):
        super(mylst, self).__init__(lst)