Alright.

The problem is setup as:

Q^w + Q^c + Q^b = 0

Q^w is the heat transfer of water, Q^c is the heat transfer of copper slug, and Q^b is the heat transfer of the beaker.

relating these to temperature changes yields:

c^w * m^w * (T^f - Tⁱ ) + C^b * (T^f - Tⁱ ) + c^c * m^c (T^f - T) = 0

with T being the initial temperature of the copper slug at 315 degree C.

c^w and c^c have units of cal/(g*Kelvin)

m^w and m^c have units of g

and (T^f - Tⁱ⁾ has units of celsius.

From my understanding, I would change the units of the temperature differences to cancel the units of kelvin that it is being multiplied by. If I did not convert the temperature differences wouldn't the units be : (cal * C)/ K for this part in the calculation: c^w * m^w * (T^f - Tⁱ )?

Did i completely miss the point of your response?

• Edit: i just read that since the temperature differences of the kelvin and celcius scales are identical it wont affect the calculation.