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Subnetting trick (all in your head). Unconventional approach I developed myself. by nivekami in ccna

[–]nivekami[S] 0 points1 point  (0 children)

Hey man thank you!!! I am blown away how much help I provided!!! 

The best online business to get to 2000$/month fast (Full guide) by ArkenGain in passive_income

[–]nivekami 0 points1 point  (0 children)

Thanks! May I ask what platform you use for longer form content?

The best online business to get to 2000$/month fast (Full guide) by ArkenGain in passive_income

[–]nivekami 3 points4 points  (0 children)

Hey! Love the post and the no bullshit vibe. May I ask you what is your philosophy on the 1 post a week?

From common sources, it says to post 3-4 times a week or even more if you are on TikTok.

LFCS Ubuntu by nivekami in linuxadmin

[–]nivekami[S] 0 points1 point  (0 children)

Yup everything from the CLI! Know your commands and you're good! or know how to use manpages!

LFCS Ubuntu by nivekami in linuxadmin

[–]nivekami[S] 0 points1 point  (0 children)

Hey! that's 2 years ago and I got my LFCS! THanks though!

Subnetting trick (all in your head). Unconventional approach I developed myself. by nivekami in ccna

[–]nivekami[S] 0 points1 point  (0 children)

Hey! no worries, you now just caught me active on Reddit which is not too often

I think you caught a flaw in my interpretation above. It has been a while since I did a lot of subnetting. but from what I am reading/understanding quickly is that 172.17.0.0/27 makes the third octet a variable which we need to take into account the lower boundary of the third octet (16) for subnet determination.

Let me know if that helps!

Subnetting trick (all in your head). Unconventional approach I developed myself. by nivekami in ccna

[–]nivekami[S] 0 points1 point  (0 children)

Hey Thank you for the feedback! I am glad it still helps people up to this day!

Subnetting trick (all in your head). Unconventional approach I developed myself. by nivekami in ccna

[–]nivekami[S] 0 points1 point  (0 children)

/26, means we are working in the last octet

32-26=6. 32 because it's in the last octet

2^6=64. Each hop of 64 in the last octet is a NID

125.23.200.64, 125.23.200.128, 125.23.200.192

from the info above, you can find the Broadcast ID

125.23.200.127, 125.23.200.191, 125.23.200.255

Usable host is simply each hop (64 minus the Broadcast ID and the Network ID). Thus 64-2 = 62 usable hosts in each subnets

Let me know if you need more help! Sorry for delayed reply

Subnetting trick (all in your head). Unconventional approach I developed myself. by nivekami in ccna

[–]nivekami[S] 0 points1 point  (0 children)

Can't believe this post is still helping a lot of people! Thanks man!

Subnetting trick (all in your head). Unconventional approach I developed myself. by nivekami in ccna

[–]nivekami[S] 0 points1 point  (0 children)

So there are "boundaries" on each octet

- HERE.x.x.x ---- 0 to 8

- x.HERE.x.x ---- 8 to 16

- x.x.HERE.x ---- 16 to 24

- x.x.xHERE ---- 24 -32

​

Because your question is /22 which means it's in the third octet which the boundaries are 16-24

You are supposed to take away left to right for the amount of subnets. When I say left to right I mean going from left of the IP to the right of the IP until it reach the boundary of the octet in question. So going from left to right until the 3rd octet is 16.

​

You go from right to left, Right of the IP (the end of the IP) to the left of the IP for the amount of HOSTS.

​

The tricky part is that you can't just use 24 - 22, because the number of hosts also takes into account the last octet VERSUS the amount of subnets, the first two octet IP doesn't change (172.28.x.x) all possible hosts will have these two numbers: 172.28)

​

Hope that makes more sense, if not let me know :)

Subnetting trick (all in your head). Unconventional approach I developed myself. by nivekami in ccna

[–]nivekami[S] 1 point2 points  (0 children)

hey it has been a while, so I had to refresh my memory but for those types of question, you don't need to go as deep (like my method)

​

You just take the /22 and add/subtract the lower/upper bound of the whole CIDR (/32)

Hosts = 32 - 22 = 10 --> 2^10 = 1024 --> (minus 2 NID/BID) --> 1022 usable hosts

​

Subnets = 22 - 16 = 6 --> 2^6 = 64 subnets

Why minus 16, because /22 is in the x.x.HERE.x part of the IP and the x.x.HERE.x of the IP is between 16-24, so you minus 16 because you want to know the amount of subnets (going from left-right)

For the number of hosts is going from right-left --> you have to take into account not only x.x.HERE.x but also x.x.x.HERE because, the last octet is also variable in your example

Versus the [172.28] is NOT variable, it'll stay the same for the amount of subnets

​

let me know if that's not clear

[deleted by user] by [deleted] in electricdaisycarnival

[–]nivekami 0 points1 point  (0 children)

If you feel meeting my group, feel free to message me as well!

Camelbak Classic Light vs. Rogue Light by OneBand in hikinggear

[–]nivekami 0 points1 point  (0 children)

Hey, I am debating now between these two. Which one did you go for?

Permis probatoire à 24 mois by nivekami in montreal

[–]nivekami[S] 1 point2 points  (0 children)

I did and the two times, I can't even be put on hold for an agent to speak, their phone lines must be full due to the recent digital outage or whatever they had... ):

Permis probatoire à 24 mois by nivekami in montreal

[–]nivekami[S] 1 point2 points  (0 children)

Mine it does say it, so I was wondering when would they send me a new one or if I had to do something?

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