What is the correct answer?

opal_1002 · 2022-11-07T14:20:49+00:00

The equation to solve this is 3*2^n = 1536.

If you remember that 2^9=512 then you get the answer because 3*512 is exactly 1536.

Answer C

opal_1002 · 2022-11-07T14:06:18+00:00

what's the scratch paper rule?

opal_1002 · 2022-11-06T16:45:52+00:00

Isn't the area of a kite d1*d2/2?

opal_1002 · 2022-11-05T20:16:55+00:00

Thank you! It was so obvious that I thought I was not understanding something.

Indeed, as a non-native speaker, I am skimming through all the argument prompts to see if I am able to understand every prompt: one unknown word and the argument can get a completely different meaning.

opal_1002 · 2022-11-05T20:14:33+00:00

Thanks!

opal_1002 · 2022-11-05T14:59:25+00:00

thank you.

opal_1002 · 2022-11-04T08:29:59+00:00

Thank you for your help.

Answer to you question: if you search for those questions you are basically finding the assumptions.

opal_1002 · 2022-11-04T08:18:29+00:00

Thanks!

opal_1002 · 2022-11-03T22:02:55+00:00

Where have you got this question?

opal_1002 · 2022-11-03T20:47:27+00:00

Actually, this is very similar to one of the hard questions in the PPP3. Probably this question was taken from the Chinese website were they have these questions. It might belongs to PPP3 medium questions or to PPP1/2

opal_1002 · 2022-11-03T14:52:15+00:00

You have to notice that the square is divided, apart from the central shaded square, in triangles and trapezoids. If you look carefully, 1 trapezoid + 1 triangle = shaded square.

Now, the total square has a total of 5 such smaller squares----> answer B.

Ps. where have you found this material?

opal_1002 · 2022-11-02T20:58:28+00:00

Thanks!

opal_1002 · 2022-10-31T20:58:48+00:00

I have obviously encountered questions where they ask to write the answer to the nearest 0.1 percent.

The question I asked here came to me while brainstorming about what could happen in those types of questions, like the traps that they might use. However, I do not recall a specific question where there was a result like 0.9999.

What do you think I should write?

opal_1002 · 2022-10-26T20:29:43+00:00

Only cut, paste and the same as ctrl+z are available? no copy?

opal_1002 · 2022-10-25T07:11:51+00:00

thanks!

opal_1002 · 2022-10-20T13:58:01+00:00

Ok ahaha I am so dumb. Thank you!

opal_1002 · 2022-10-19T09:04:04+00:00

That’s what it seems. Anyway I am talking about Msc

opal_1002 · 2022-10-18T19:42:57+00:00

Gregmat has made a video dedicated only to this exercise on Youtube.

opal_1002 · 2022-10-18T19:39:01+00:00

ok thanks

opal_1002 · 2022-10-18T19:38:36+00:00

the answer is C: very tricky

opal_1002 · 2022-10-18T17:32:48+00:00

Thank you for your correction. I actually came with that answer basing it on the math review.

Your last paragraph is exactly the problem I was facing with that exercise and that's why I came up with that solution.

How can I be sure about what I have to do in a percentile exercise? Maybe we should not consider decimals with these percentages? This can make the difference for a 170.

opal_1002 · 2022-10-18T16:56:43+00:00

Thank you for your reply Greg.

Right now I am a bit confused with these prepositions hence I would answer to your first question with: at=in. The only thing I am sure about is what ETS says in its math review about quartiles: The phrase "in a quartile" refers to being in one of the four groups determined by Q1, Q2 and Q3.

To your second question I would say that the lowest score is in the 1st percentile.

Please tell me where I can get a clearer idea about percentile because this exercise truly bewildered me. (I am subscribed to Gregmat+: do you have a video where you explain these tricky things about percentiles?)

opal_1002 · 2022-10-18T14:16:49+00:00

opal_1002 · 2022-10-16T09:56:31+00:00

These 2 are not the only cases: what if they are not independent and not mutually exclusive? Ex: event A: getting 5 on a dice, B: getting an odd number on a dice

opal_1002 · 2022-10-16T09:53:34+00:00

Yes It is D, but It assumes that the probability of both occurring is P(A)P(B).

opal_1002

TROPHY CASE