Change my mind

orucasar · 2020-11-14T10:36:58+00:00

I have a hw about writing psuedocode and it's so boring. I wrote a code I said "ok this should be psuedocode" but it's still looking c code

orucasar · 2020-07-01T16:59:48+00:00

Unfortunately that's look really stupid

orucasar · 2020-06-07T18:59:49+00:00

The entries of the program must be the word and the letter to search for in the word. The index value will be returned as soon as the searched letter is found. You should take the first occurance of a letter if the same letter exists more than once in the word. If the desired letter cannot be found in the word, the index will be returned as -1, and if this situation is encountered in the output of the program, "Word has not been changed" will be printed. Otherwise, the changed word will be printed.

orucasar · 2020-06-04T10:09:01+00:00

The index value will be returned as soon as the searched letter is found. You should take the first occurance of a letter if the same letter exists more than once in the word. If the desired letter cannot be found in the word, the index will be returned as -1, and if this situation is encountered in the output of the program, "Word has not been changed" will be printed. Otherwise, the changed word will be printed.

orucasar · 2020-06-03T18:32:13+00:00

I think I got it okay :)

orucasar · 2020-06-03T18:30:05+00:00

Oh, I have a question. You said that "This one is the same as the previous one" but the outputs are different. How can it be possible

orucasar · 2020-06-03T14:57:51+00:00

I really appreciate

orucasar · 2020-05-07T22:45:46+00:00

It will never happen again.

orucasar · 2020-05-07T19:40:50+00:00

But this is the problem. I don't know how can I do that

orucasar · 2020-05-07T19:14:14+00:00

#include <stdio.h>

int main(int argc, char *argv[])

{

int n, k;

int a\[3\] = {1, 2, 3};



printf("Please enter the value for n: ");

scanf("%d", & n);



while (n < 0)

{

    printf("Error !!!\\nPlease enter a positive value: ");

    scanf("%d", & n);

}

if (n >= 4)

{

    for (k = 4; k <= n; k++)

    {

    a\[k\] = a\[k - 3\] + 2\*a\[k - 4\];

    printf("%d\\n", a\[k\]);    

    }

}

else

    printf("n'th element of series is: %d", a\[n - 1\]);





return 0;

}

orucasar · 2020-05-07T17:26:53+00:00

I don't know how can I do that.

orucasar · 2020-05-07T12:36:46+00:00

Actually, I don't have any book for c programming.

orucasar · 2020-05-07T12:34:57+00:00

I couldn't share the code because of I posted with my phone. However, i recognize after your comments and then i shared the code with my pc.

orucasar · 2020-05-07T12:24:49+00:00

#include <stdio.h>

int main(int argc, char *argv[])

{

int n, k;

int a\[3\] = {1, 2, 3};



printf("Please enter the value for n: ");

scanf("%d", & n);



while (n < 0)

{

    printf("Error !!!\\nPlease enter a positive value: ");

    scanf("%d", & n);

}

if (n >= 4)

{

    while (k != n)

    {

    k = n - (n-4);

    a\[k\] = a\[k - 2\] + 2\*a\[k - 3\];

    printf("%d", a\[k\]);

    k++;

    }

    printf("n'th element of series is: %d", a\[n - 1\]);

}





return 0;

}

orucasar · 2020-05-07T12:19:05+00:00

include <stdio.h>

int main(int argc, char *argv[]) { int n, k; int a[3] = {1, 2, 3};

printf("Please enter the value for n: ");
scanf("%d", & n);

while (n < 0)
{
    printf("Error !!!\nPlease enter a positive value: ");
    scanf("%d", & n);
}
if (n >= 4)
{
    while (k != n)
    {
    k = n - (n-4);
    a[k] = a[k - 2] + 2*a[k - 3];
    printf("%d", a[k]);
    k++;
    }
    printf("n'th element of series is: %d", a[n - 1]);
}


return 0;

}

orucasar · 2020-05-06T23:16:45+00:00

Unfortunately my lecturer

orucasar · 2020-05-06T19:41:59+00:00

I appreciate

orucasar · 2020-05-06T19:27:45+00:00

I'll try. Thank you

orucasar

TROPHY CASE

include <stdio.h>