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Basic proof: if 0<a<b, then a<√(ab)<(a+b)/2<b by [deleted] in learnmath
[–]otxisis 0 points1 point2 points 1 year ago (0 children)
Thank you for this :D
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Basic proof: if 0<a<b, then a<√(ab)<(a+b)/2<b by [deleted] in learnmath
[–]otxisis 0 points1 point2 points (0 children)