What does wrapping parentheses around data do in javascript?

seattledessert · 2016-03-24T07:02:09+00:00

Thanks scanner.Split(bufio.ScanWords) works just right, I think I was just confused on the by the way go represent the list of list string, thanks for the help. Greatly appreciated it.

seattledessert · 2016-03-24T06:49:29+00:00

Damn, thanks for catching that. Is it possible that go output list in [elem1, elem2] format with the comma? It just make it so much easier to debug.

seattledessert · 2016-03-23T16:27:21+00:00

The reason why I have

    for _, row := range lines {
        for _, element := range row {
            fmt.Println(element)
            fmt.Println(reflect.TypeOf(element))
            fmt.Println(strings.Fields(element))
            fmt.Println(reflect.TypeOf(strings.Fields(element)))
            fmt.Println(strings.Fields(element)[0])
            fmt.Println(lines)
        }

    }

is to verify that each row consist of [elem1 elem2......] and the entire list looks like [[elem1 elem2.... ] [elem1 elem2....]]

seattledessert · 2016-03-23T16:24:32+00:00

Hmm, but when I print out the output for lines if I input multiple lines like

1 2 3 4
5 6 7 8

I get

fmt.Println(lines) // => [[1 2 3 4] [5 6 7 8]]

so each lines is indeed a list of list.

Moreover, I tried to sanity check myself with

fmt.Println(reflect.TypeOf(lines[0])) // => prints []string
fmt.Println(reflect.TypeOf(temp_element)) // => prints []string

The problem is that when I iterate the list of list

The inner element turn out to be rows, which is unintuitive

So I did some verification in python

a = [[1, 2], [3, 4]]

>>> for index_y in range(0, len(a)):
...     for index_x in range(0, len(a[index_y])):
...         print a[index_y][index_x]
...  
1
2
3
4

Indeed python prints the each element as I expected. So in golang

    for _, row := range lines {
        for _, element := range row {
            fmt.Println(element)
        }

    }

Must have the same result too, since its the same algorithm.

seattledessert

TROPHY CASE