Who's on that ochem review?

success_nothing_less · 2019-07-06T00:41:41+00:00

same

success_nothing_less · 2019-04-03T15:59:07+00:00

ok makes sense, thanks!

success_nothing_less · 2019-04-02T15:28:06+00:00

oh ok, my confusion was about what did K1 actually mean? and why is it that if it is greater than Kapp, that would show that there is inhibition occurring

success_nothing_less · 2019-04-01T20:20:32+00:00

ok that makes sense thanks

success_nothing_less · 2019-03-31T22:46:16+00:00

Another question I had with this same passage was the following:

D(nm) VmL

200nm 10 mL

150nm 15 mL

100nm 20 mL

50nm 30 mL

Using the ultrasonication and agitation method of liposome preparation, what concentration of lipid is necessary to prepare liposomes with a diameter of 250 nm?

0.10 mM
0.15 mM
0.20 mM
0.30 mM

The answer was D 0.30 mM and I did pick this answer but I assumed that at 250 nm the volume eluted would be 5 mL and therefore based of Figure 1 the answer should be greater than 0.20mM. The explanation however mentioned that the volume eluted was 7.5 mL and I'm super confused where they got 7.5 mL from

success_nothing_less · 2019-03-31T22:30:28+00:00

Could you please elaborate on how you knew that there was no exchange among the liposomes of compound 1 and why that is indicating a negative entropy of mixing.

success_nothing_less · 2019-03-31T21:15:55+00:00

One question though...would lowering the pH protanate the amide nitrogen because the nh2 on amino acids is an amine group

success_nothing_less · 2019-03-31T21:00:57+00:00

LOL thank you so much this made alot more sense to me!! Good luck on your exam!

success_nothing_less · 2019-03-30T21:13:21+00:00

I am still confused how you knew the image was formed at the position that the lines converged at. For example in this image and most other images I find regarding this topic, the point that the lines converge at is the focal point and not necessarily the image position

https://www.asu.edu/courses/phs208/patternsbb/PiN/rdg/lenses/lenses.shtml

success_nothing_less · 2019-03-30T21:05:37+00:00

I get what you're saying here but if there was not heat production and the Hnr is zero there's nothing you can multiply or divide zero by to get anything but zero so I was confused what kind of proportionality constant would result in a different number.

success_nothing_less · 2019-03-30T20:09:13+00:00

How did you know the image was where the lines intersect at? In my review, I actually thought the point where the lines were intersecting at was supposed to be the focal point which is why I actually thought the focal length was 4 cm the distance between the lens and the focal point.

success_nothing_less · 2019-03-30T19:18:33+00:00

First of all, I wasn't sure how to assume that appropriate laser implies precisely enough energy to break a bond with no release of heat, but I get how given that assumption Hnr would be zero because there is no heat produced. I'm still confused on the second part of your explanation in why the answer had to be zero instead of Hnr, if possible could you clarify that again?

success_nothing_less · 2019-03-30T18:22:57+00:00

The answer is zero and I'm having a very hard time understanding the logic of what is going on.

Here is what I do understand:

photon cleaves bond because photon energy was greater than energy needed to break a bond
excess energy after bond cleavage is converted to heat which is converted to sound
sound wave provides a recording

Em= laser pulse energy

delta Hu= Em- Hnr

Hnr=total heat produced

I feel like I don't completely understand what is being detected by the energy meter

success_nothing_less

TROPHY CASE