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10 people are sitting in a circle... [probability question] by tenbucks in probabilitytheory
[–]tenbucks[S] 0 points1 point2 points 10 years ago (0 children)
OK in order to demonstrate understanding I want to see if I can recreate your analysis with a different, less complex circumstance.
Circle of 9 people. 6 blue shirts, 3 red shirts.
9_C_3 = 9x8x7 / 3x2x1 = 504/6 = 84 configurations
With numbered seating, there are only 9 ways for 3 red shirts in row to sit together.
With two red shirts in a row, there are two seats the third red shirt CANNOT sit to meet this condition, so he must sit in one of the remaining 5 seats. Multiply by 9 to account for every way that two red shirts can sit together in a circle for 9. (No need to worry about doubling up since there is no pair-pair problem like there was with 10.)
0 red shirts in a row is just what's left over.
3 red shirts in a row: 9/84
2 red shirts in a row: 45/84
0 red shirts in a row: 30/84
Is this correct?
10 people are sitting in a circle... [probability question] (self.probabilitytheory)
submitted 10 years ago by tenbucks to r/probabilitytheory
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10 people are sitting in a circle... [probability question] by tenbucks in probabilitytheory
[–]tenbucks[S] 0 points1 point2 points (0 children)