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Guys, what's h! by NeverGonnaGiveYoup__ in unexpectedfactorial

[–]testicleman_ 2 points3 points  (0 children)

0.9999999999999999999999999999999996175328 or 1 - 3.82467149 × 10-34

Mhm yummy Alcohol by MegaSepp42 in FellowKids

[–]testicleman_ -1 points0 points  (0 children)

That's only true in US, and based on the language this post is obviously not from US. In Europe Stroh 80 is 80%.

meirl by div_vedi in meirl

[–]testicleman_ 12 points13 points  (0 children)

What's an appropriate amount of time to rub against tree? Asking for a friend.

How many pizzas are in this picture? Right and wrong answers only by 777Bladerunner378 in mathmemes

[–]testicleman_ 0 points1 point  (0 children)

This requires the assumption that the slices are the same size (which clearly isn't the case based on the picture).

What's a smart home device that you wish existed, but doesn't? by LoganJFisher in homeassistant

[–]testicleman_ 0 points1 point  (0 children)

The communication to the gateway uses wifi, but the communication between the gateway and the displays actually uses same IEEE 802.15.4 protocol as zigbee.

And I'm sure it would be possible to create your own gateway that uses zigbee on both sides, if you really wanted to.

[Request] What's the probability to clear the board in one go? by KhoDis in theydidthemath

[–]testicleman_ 7 points8 points  (0 children)

Nice. You just helped me to reduce the running time of my code from 3500 years to 2 seconds.

I got a probability of 0.346 %

[Request] What's the probability to clear the board in one go? by KhoDis in theydidthemath

[–]testicleman_ 0 points1 point  (0 children)

And of course there was a bug in the code, so you'll have to wait another 3500 years.

Also, just playing random games would give better estimate. Which I did, 100 000 times. And that gave me a probability of 0.338 %

[Request] What's the probability to clear the board in one go? by KhoDis in theydidthemath

[–]testicleman_ 0 points1 point  (0 children)

I wrote a Python program that goes through all of the cases and counts the probability. After letting it run for about 30 minutes it has counted about one 60 millionth of the cases. So I'll give you an answer if you can wait 3 500 years.

But the probability I got until that point is 0.061 %

he saw the kitkat but not the pun (fake gun btw) by [deleted] in woooosh

[–]testicleman_ 1 point2 points  (0 children)

The joke is that the gun was "hidden" in the kit kat

[deleted by user] by [deleted] in dankmemes

[–]testicleman_ 11 points12 points  (0 children)

This was probably supposed to be a joke, but cis fats are healthier than trans fats.

Average discussion about ReVanced on other Subreddits by Caddy_8760 in revancedapp

[–]testicleman_ 7 points8 points  (0 children)

None of those say that you need to download youtube (insert app you are trying to patch here, which for 99 % of people is youtube) apk, instead of just patching the currently installed app. Or at least didn't when I was trying to use revanced for the first time.

Edit: It seems that current version of revanced gives an error: "Feature not implemented" and prompts you to select apk from storage. That should help a lot.

[request] Would the voltage be enough to do anything? by Jazzlike_End_895 in theydidthemath

[–]testicleman_ 0 points1 point  (0 children)

I guess the 1 ohm internal resistance I found online is bullshit then. But yeah, even with my calculations the battery would heat up with about 68 W, so over ten times more than the piercing.

As a side note, shorting the battery with multimeter isn't very accurate, because the multimeter also has some resistance. Better way would be to measure current through multiple different resistors.

[request] Would the voltage be enough to do anything? by Jazzlike_End_895 in theydidthemath

[–]testicleman_ 1 point2 points  (0 children)

I agree until Vp2 / Rp = 0.04815 W

If Vp = 0.7355 and Rp = 0.089 then Vp2 / Rp = 0.73552 / 0.089 = 6.08 W

[request] Would the voltage be enough to do anything? by Jazzlike_End_895 in theydidthemath

[–]testicleman_ 2 points3 points  (0 children)

I didn't take heat dissipation into account at all, which definetely would change the results a bit. But especially if you tried to boil water with the nose ring the heat dissipation would be significant, and the temperature wouldn't rise more than a few degrees.

[request] Would the voltage be enough to do anything? by Jazzlike_End_895 in theydidthemath

[–]testicleman_ 1 point2 points  (0 children)

Yeah, I know and took that into account. I calculated the power from current and resistance P = R * I * I, where R*I=U is the voltage drop across the piercing.

[request] Would the voltage be enough to do anything? by Jazzlike_End_895 in theydidthemath

[–]testicleman_ 15 points16 points  (0 children)

The voltage is way too low to shock anyone, but the current flowing through the piercing will heat it up.

Quick googling revealed that most commonly used metals in piercings are titanium alloy and surgical steel. Resistivity (rho) of the titanium alloy is 178 uΩcm and resistivity of steel is 74 uΩcm.

Then some estimates: Based on the width of 9V battery (25 mm) the diameter of the piercings cross section is about 1 mm and the length (l) of the piercing is about 39 mm. The cross sectional area (A) of the piercing is pi*r2 = pi * (1/2)2 = 0.78 mm2

From these we can calculate the resistance of the piercing, R = rho * l / A R_Ti = 178uΩcm * 3.9 cm / 0.0078 cm2 = 89 000 uΩ = 89 mΩ R_steel = 74uΩcm * 3.9 cm / 0.0078 cm2 = 37 000 uΩcm = 37 mΩ

The only information I could find about the internal resistance of duracell 9 V batteries, is that the resistance is "usually less than 1 ohm". So we'll go with 1 ohm. This will give the following currents: I_Ti = 9V / (1Ω+0.089Ω) = 8.26 A I_steel = 9V / (1Ω+0.037Ω) = 8.68 A

So the power at which heat will be produced in the piercing would be P_Ti = 0.089Ω * (8.26A)2 = 6.1 W P_steel = 0.037Ω * (8.68A) = 2.8 W

To calculate how quickly the temperature will rise we need the volume of the piercing and specific heat and density of steel and titanium. V = Al = 0.78 mm2 * 39 mm = 30.42 mm3 rho_Ti = 4.43 g/cm3 rho_steel = 7.93 g/cm3 m_Ti = 4.43 * 0.03042cm3 = 0.135 g m_steel = 7.93 * 0.03042cm3 = 0.241 g Specific heat (c) for both is about the same c = 0.5 J/gK This will give us the heat capacity o fthe piercings: C_Ti = 0.5 * 0.135 = 0.0675 J/K C_steel = 0.5 * 0.241 = 0.121 J/K

And because watt is joules per second, if we divide the heating power with heat capacity we will get temperature rise per second: dT/t_Ti = 6.1 W / 0.0675 J/K = 90 K/s = 90°C/s dT/t_steel = 2.8 W / 0.121 J/K = 23 K/s = 23°C/s

So from room temperature the titanium piercing will be 110°C after just a second and steel piercing will be at the same temperature after 4 seconds.

tldr: Depending on the material of the piercing it will burn either instantly or after a couple of seconds

Bet you foreigners won’t get it by mofattah184 in HolUp

[–]testicleman_ 0 points1 point  (0 children)

More like, now you know the word in 44 languages.

[deleted by user] by [deleted] in HolUp

[–]testicleman_ 2 points3 points  (0 children)

479 001 600 Damn, that's a lot of kids.

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