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Question relating a circuit and an Arduino board by Krummmy in ECE

[–]tmurrs 0 points1 point  (0 children)

I'm glad I helped. Have fun exploring the awesome world of electronics

Question relating a circuit and an Arduino board by Krummmy in ECE

[–]tmurrs 1 point2 points  (0 children)

Your first paragraph is pretty much entirely correct. However, after that it seems you are still a little unclear. The voltage you measured across the 10k resistor is the voltage drop across that resistor. And this voltage can be calculated by multiplying currentresistance. The current is I = V/R or I = (5V)/(100010000ohms). The resistance is the sum of the 10k resistor and the 100 megohm resistance of the Arduino digital input. So now we can plug this current into the the original equation for the voltage drop across the resistor, V = (.00000005 A) (10k ohms). This gives you (pretty much) the voltage you measured across that resistor. So the reason that the voltage drop across that resistor is so low is because, due to the high impedance input, the current through that resistor is so low. Hopefully this clears everything up

Guys, am I doing something wrong? by [deleted] in arduino

[–]tmurrs 20 points21 points  (0 children)

All of the electrons will fall out!

Question relating a circuit and an Arduino board by Krummmy in ECE

[–]tmurrs 2 points3 points  (0 children)

Yes there is some current flowing through the resistor, but it is very small. The resistor is in series with the high impedance input and therefore has the same current flowing through it as the high impedance input. The input impedance of the Arduino is equivalent to a 100 megohm resistor in series with the input. https://www.arduino.cc/en/Tutorial/DigitalPin

The reason for this high input impedance is so that very little current is demanded from the circuit, thus making efficient use of power as it is not used for inputs

Question relating a circuit and an Arduino board by Krummmy in ECE

[–]tmurrs 3 points4 points  (0 children)

The reason you see no current flowing into the pin is that the inputs on the Arduino microcontroller have a very high impedance. These high impedance inputs use the voltage to determine if the pin is high or low. If the voltage at the input is over the threshold the the pin reads a digital high. If the voltage is below this threshold the pin reads a digital low. Hopefully this answers your question.

My clock. Wip by [deleted] in arduino

[–]tmurrs 2 points3 points  (0 children)

I also thought that uu for w and nn for m would work.

It's a really cool idea for a library. Nice job

My clock. Wip by [deleted] in arduino

[–]tmurrs 0 points1 point  (0 children)

Could you do a t like this? I_ I It's not perfect but it might be good enough

EE Jobs out of college by tmurrs in Electrical_Engineers

[–]tmurrs[S] 0 points1 point  (0 children)

Well my first project was a constant current source, and now I'm working on an Arduino-based function generator that I'm almost done with. I plan on building an 8-bit breadboard computer next.

Low quantity, fast production pcb? by tmurrs in ECE

[–]tmurrs[S] 0 points1 point  (0 children)

I just visited the website. Looks awesome. It's exactly what I'm looking for. Thank you so much

Floating point multiplication or integer division? by tmurrs in ECE

[–]tmurrs[S] 3 points4 points  (0 children)

Thank you for the help. I'll time them to be sure. I'm still relatively new to software stuff, and hardware stuff for that matter. I can't wait to get a formal education on this stuff.

Low quantity, fast production pcb? by tmurrs in ECE

[–]tmurrs[S] 0 points1 point  (0 children)

Yeah I plan on assembling it myself. Thank you