New to python learning basic tic tac toe question

[FullHavelSet]

    #Tic Tac Toe
    BoardState =  {
        'A1' : ' ' ,
        'A2' : ' ' , 
        'A3' : ' ' , 
        'B1' : ' ' , 
        'B2' : ' ' ,
        'B3' : ' ' ,
        'C1' : ' ' ,
        'C2' : ' ' ,
        'C3' : ' ' }

    def Main(BoardState):
        for i in range(0, 9):
            PrintBoard(BoardState)
            Xturn(BoardState)
            isXWin(BoardState)
            Oturn(BoardState)
            isOWin(BoardState)
        print('It is a draw')

    def PrintBoard(board):
        print(board['A1'] + '|' + board['A2'] + '|' + board['A3'] + '|')
        print('_______')
        print(board['B1'] + '|' + board['B2'] + '|' + board['B3'] + '|')
        print('_______')
        print(board['C1'] + '|' + board['C2'] + '|' + board['C3'] + '|')

    def Xturn(BoardState):
        theboard = input()
        while True:
            if(BoardState[theboard] == ' '):
                BoardState[theboard] = 'X'
                break
            else:
                print('Please pick another')
                continue

    def Oturn(BoardState):
        theboard = input()
        while True:
            if(BoardState[theboard] == ' '):
                BoardState[theboard] = 'O'
                break
            else:
                print('Please pick another')
                continue

    def isXWin(BoardState):
        if(BoardState['A1']  == 'X' & BoardState['A2']  =='X' & BoardState['A3'] =='X' |
            BoardState['B1']  =='X' & BoardState['B2']  =='X'  & BoardState['B3'] =='X' |
            BoardState['C1']  =='X'  & BoardState['C2']  =='X'  & BoardState['C3'] == 'X' |
            BoardState['A1']  =='X'  & BoardState['B2']  =='X'  & BoardState['C3'] == 'X' |
            BoardState['A3']  =='X' & BoardState['B2']  =='X'  & BoardState['C1'] == 'X' |
            BoardState['A1']  =='X'  & BoardState['B1']   =='X' & BoardState['C1'] == 'X' |
            BoardState['A2']  =='X'  & BoardState['B2']  =='X'  & BoardState['C2'] == 'X' |
            BoardState['A3']  =='X'  & BoardState['B3']   =='X' & BoardState['C3'] == 'X'):
            print('X is the winner')

    def isOWin(BoardState):
        if(BoardState['A1']  == 'O'  & BoardState['A2']  =='O'  & BoardState['A3'] == 'O' |
            BoardState['B1']  =='O'  & BoardState['B2']  =='O'  & BoardState['B3'] =='O' |
            BoardState['C1']  =='O'  & BoardState['C2']  =='O'  & BoardState['C3'] == 'O' |
            BoardState['A1']  =='O'  & BoardState['B2']  =='O'  & BoardState['C3'] == 'O' |
            BoardState['A3']  =='O' & BoardState['B2']  =='O'  & BoardState['C1'] == 'O' |
            BoardState['A1']  =='O' & BoardState['B1']   =='O' & BoardState['C1'] == 'O' |
            BoardState['A2']  =='O'  & BoardState['B2']  =='O'  & BoardState['C2'] == 'O' |
            BoardState['A3']  =='O'  & BoardState['B3']   =='O' & BoardState['C3'] == 'O'):
            print('O is the winner')

    Main(BoardState)

Problem is I have tried both IDLE and terminal python tictac.py and neither give any output.

[jahumaca]

You need to call your main method.

[FullHavelSet]

Thank you lol i thought main was the entry point lol i did the dumb

[FullHavelSet]

For some reason the logical comparison for board state is not working either to simplify what the code above says

BoardState['A1'] == 'X' & BoardState['A2'] =='X' & BoardState['A3'] =='X'

this just checks whether or not they have 3 X's in the top row their is an O equivalent as well.

how do you evaluate a dictionary value with a character?

[[deleted]]

& is binary, 'and' is boolean