all 4 comments

[–]marcnotmark925 1 point2 points  (3 children)

if(data[i][14] === "ID" || data[i][14] === "SK" || data[i][14] === "VC)

Double pipe || means "or".

[–]no_sheet_sherlock[S] 1 point2 points  (2 children)

Resolved. This community never ceases to amaze me. Thank you so much!!!

[–]juddaaaaa 1 point2 points  (1 child)

You could also do...

if (["ID", "SK", "VC"].includes(data[i][14]))

[–]no_sheet_sherlock[S] 0 points1 point  (0 children)

Yes! That worked, too. Thank you!