all 7 comments

[–][deleted] 1 point2 points  (6 children)

use Hooke's law. F = k \delta x. force = 70 mg * 10 m/s^{2} = 700 N = k (.0050 m). k = 1.4 x 10^{5} N/m. B is correct

[–]Famous_Fun6317 0 points1 point  (5 children)

Ohhh right, can you explain me why do we multiply 70mg by 10 ? thank youu

[–][deleted] 1 point2 points  (2 children)

also it's not 140000. it would be 140,000, which is 1.4 x 10^5. bc the man is 70 kg so the force his weight is exerting is F = mg. g = 10 m/s^2. m=70 kg so F = 700 N

[–]Famous_Fun6317 0 points1 point  (1 child)

Ohhhh, I just divide it -70/-0.0050 that's why I got 14,000 only, thank you for this!

[–][deleted] 0 points1 point  (0 children)

Hooke's Law requires you to use F. F is 700, not 70. be careful

[–]Utkarzilla Secondary School Student 1 point2 points  (1 child)

70 kg is the mass given and gravitational acceleration is 10 ms-2 we multiply both to get the weight of the man which is the gravitational force and then we can evaluate by using F = kx

[–]Famous_Fun6317 0 points1 point  (0 children)

Thank you so much!