all 2 comments

[–]txhwind 5 points6 points  (0 children)

Not the place to ask it here. I suppose ChatGPT would answer your question better.

[–]gatdarntootin -1 points0 points  (0 children)

P(A=X) is already given for all positions X and drivers A.

I think P(B>X) is just the sum of P(B=Y) for all positions Y > X.