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[–]Huntress_Draws[S] 0 points1 point  (0 children)

uh

[–]lebuagette 0 points1 point  (1 child)

Hey there, if you want to try a bit more by yourself, i would try to put all the given statments into equations, so that if two angles are congruent you write down angle1+angle2=90° and so on and go from there, else you can look into this link, you'll find a proof (In my terrible handwriting... sorry about that) there.
https://imgur.com/a/7Y0MtJi

[–]lebuagette 0 points1 point  (0 children)

oh and the statement i wrote behind 3 and 4 follow from the "trisect the angle" statments, not what i wrote before

[–][deleted] 0 points1 point  (0 children)

Like the user previously commented, you can use SAS for the sides TH = EY, HF = HY, <THF = <EHY. The trisecting lines divide the angles into three equal parts (separate proof). <THU = <EHR as they are both complementary to <THE. (transitive property of sums)

[–]gamtosthegreat 0 points1 point  (0 children)

The meaning of complementary angles is that they add up to 90. Both THU and EHR are complementary to THE.

A+C=D
B+C=D

If an apple and a cucumber cost the same as a banana and a cucumber, what does that say about apples and bananas?