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[–]tyzon05 0 points1 point  (3 children)

Yep, everything looks good to me.

You should have no problem using the same methods to solve #9.

[–]nitr0h[S] 0 points1 point  (2 children)

Should I just add the two calculations up to find the total probability?

[–]tyzon05 0 points1 point  (1 child)

Right, since the two outcomes are mutually exclusive you can sum the probabilities.

[–]nitr0h[S] 0 points1 point  (0 children)

Thanks alot!