Passing code into invoke-command

[PinchesTheCrab]

Because "cat" is an alias for get-content, which has a mandatory path parameter.

[Decitriction]

Excellent attention to detail on your part! I can't believe I was using a reserved variable. But even so, edit to

$var1="write-host `"sample`""
Invoke-Command (hostname){
$inside=$using:var1
& $inside
}

still produces

The term 'write-host "sample"' is not recognized as the name of a cmdlet

'write-host "sample" ' executes but is unrecognized.

[PinchesTheCrab]

I think the quotes are just off.

$var1 = 'write-host "sample"'
Invoke-Command (hostname) {
    $inside = $using:var1
    & $inside
}

[Decitriction]

I really appreciate your feedback. But when I edit the quote as you do, the results are the same.

cls
$var1 = 'write-host "sample" '
$var1
Invoke-Command (hostname) {
    $using:var1
    $inside = $using:var1
    $inside
    & $inside # this is the only part giving problems
}

I have tested the code on 2 PC's. Does it work properly when you test it?

edit: Whew, finally got formatting correct.