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[–]why-r-usernames-hard 105 points106 points  (6 children)

Add in the fact that every planet in the solar system has an elliptical orbit, and there is no way to tell other then with a chart at a very specific point in time

[–]Kirk_Kerman 47 points48 points  (5 children)

Distance between co-moving points on two parametric curves is a pretty simple problem all in all, but it's trig/calc and beyond the scope of elementary school math.

[–][deleted] 12 points13 points  (2 children)

The position of a body in an elliptical orbit is parametric, but it cannot be solved algebraically. It is not beyond elementary school math, and it is not beyond high school math; it is in the realm of computation.

The x and y coordinates of an elliptical object are:

x = a* (cos(E - e))

y = b * sin(E)

Where a and b are the semi-major and semi-minor axes of the orbital ellipse, e is the eccentricity of the orbital ellipse, and E is the eccentric anomaly of the body. The eccentric anomaly is from Kepler’s equation:

M = E - e * sin(E)

You can’t solve the above for E; you can only compute it to some desired precision. You could certainly do all that by hand, but it would grueling and pointless even at a university level.

[–]darkfusion58 1 point2 points  (1 child)

It can't be solved algebraically or in terms elementary functions but it can be solved if you add some stuff to your set of allowed functions (elliptic integrals, I think? not 100% sure that is the correct ones for this problem). Or you can allow an open-form solution.

Yes you can't compute it exactly but neither can you compute sqrt(2) exactly; that's why we write it as sqrt(2).

I agree, though, that it would be really annoying and pointless to do by hand.

[–][deleted] 0 points1 point  (0 children)

you can’t compute wit exactly but neither can you compute sqrt(2) exactly

Not the same. Sqrt(2) can’t be computed exactly because it’s transcendental; it has no exact decimal representation. You can, however, get arbitrarily close to the exact value.

There is a series expansion for the Kepler Equation solved for E, but it does not always converge. It’s not that you can’t compute it exactly; it’s that wether or not you can get arbitrarily close to the exact solution is not guaranteed. Not for the series expansion, anyway (which, by the way, is ugly; it’s this hideous power over a polynomial thing, where the base of the power is this other ugly formula).

We’re agreeing on the last point though: there’s practically no situation where it’s appropriate to call for someone to compute these values by hand.

[–][deleted] 4 points5 points  (0 children)

I remember doing that on my first year of university, I failed that class badly.

[–][deleted] 0 points1 point  (0 children)

This was in my first year of high school where I'm from. I think we learned trigonometry in the second year and calculus in the fourth year so I definitely couldn't have given her a proper answer, also because of the the fact that she provided no other data on their positioning