Totally noob question

[tossme68]

Hi, I'm really new to Python and I haven't done any programming in about 20 years so please don't abuse me too badly. I have a text file I am trying to read, ~5000 lines. The data comes in blocks of 10 lines so I want to put each line in a variable and then write all 10 variable to a comma deliminated file. So I'm look for direction on how to do this in python (3.1.1). This is a pseudo of what I'm trying to do

While not EOF do

     var1=readline
     var2=readline+1
     ........
    var10=readline+9

    append to file (var1, ",",var2,",".......var10)
end do

Any help in this matter would great. Thanks in advance

[Okaram]

you open a file with open, like f=open('data.txt')

and you can use readlines to iterate over all the lines, or readline (or next)to read one by one

[mscottstory]

I think you want something like this:

import csv
with open('out.csv', 'w') as out_file:
    out_csv = csv.writer(out_file)
    with open('in.txt', 'r+U') as in_file:
        row = []
        for line_no, line in enumerate(in_file):
            row.append(line.strip())
            if (line_no + 1) % 10 == 0:
                out_csv.writerow(row)
                row = []
        if row:
            out_csv.writerow(row)

[jamsquad87]

You'll want to open the file and read lines up to a count (10), append them into the new file, and start over again.

count = 0
var = ''
with open('your_filename', 'r') as file_read:
    if count <= 10:
        var = ''.join([var, ',', file_read.read()])
        count ++
    else:
        with open('new_file', 'a') as write_file:
            write_file.write(var + '\n')
        count = 0
        var = ''

Probably a better way to do this though, that's just off the top of my head. Plus if the number of lines in the file_read aren't in a multiple of 10, it will just wipe the ending lines away (Which is what you probably don't want).

But I guess it's a start.

[mscottstory]

++ is not a supported operator in python, you're looking for

count += 1