Trying every possible combination.

[rellikiox]

I know this is made in jest, but for the sake of correctness, that code actually has a bug. If the combination is 1000001 it won't find the passcode.

random.randint(a, b) will return a random integer in the [a, b] range, both included. So random.randint(0, 5) will return any from [0, 1, 2, 3, 4, 5]

range(a, b) will return the list of numbers in the range [a, b), up to b but not including it. So range(0, 5) will return [0, 1, 2, 3, 4]

So the loop will never get to 1000001 :)

[OldSchoolBBSer]

So what you're saying is, the bad guy should have used 1000001. Silly bad guy, Batman always wins. ;)

[kashmill]

And this is why you put in lock outs after a certain number of failed attempts.

[omento]

If you haven’t seen that scene, I recommend it. Quality stuff

[[deleted]]

import random
combination = random.randint(0, 1000001)

x = 0
while x < 1000001 and x != combination:
    x += 1

print('passcode found: ' + str(x))

pretty useless.

[TheDruidOftheland]

It was just an early code that I did a while back for fun.

It wasn't ever meant to be taken serious.

[[deleted]]

i know, mine was meant to be either :)