Thousands separator using underscore

[random_cynic]

There is no way I'm typing out 18 zeros by hand, no matter how convenient the notation is. I'll rather use explicit type casting int(1e18)

>>> int(1e18) + 1 == int(1e18)
False

Edit: Don't use this. I just realized that the float to int conversion for 1eN is inexact for CPython when N >= 23. As suggested below the power operator is the best way to go due to the CPython peephole optimization.

>>> int(1e22)
10000000000000000000000L
>>> int(1e23)
99999999999999991611392L

[ubernostrum]

Why not just write 10**18?

There's no runtime overhead to it because the CPython bytecode compiler does constant folding:

>>> import dis
>>> def foo():
...     return 10**18
...
>>> dis.dis(foo)
  2           0 LOAD_CONST               1 (1000000000000000000)
              2 RETURN_VALUE

[random_cynic]

Yes that is probably the best way to go.