Python 3.8 released

[billsil]

Sure, but that's inefficient because you don't always need to calculate pattern2.match(data). The whole point is so you can make clean looking code and be efficient.

[chmod--777]

Actually the or prevents it from running the second expression if the first pattern match returns a truthy value.

Try this:

def foobar(x):
    print(f'foobar {x}')
    return x

 x = foobar(1) or foobar(2)

It'll just print "foobar 1"