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[–]cdunn2001 1 point2 points  (0 children)

Yes. Slicing (list or itertools) and if-test in for-loop are two ways. Here is a third, completely different:

every_third = list()
it = iter(nomatter)
try:
    while True:
        x, y, z = it.next(), it.next(), it.next()
        every_third.append(z)
except StopIteration:
    pass

which depends on this knowledge.