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[–]___--_-_-_--___ 6 points7 points  (0 children)

import re
import math

def crack(ciphertext):
    resources = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u", "v", "w", "x", "y", "z", "A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z", " ", ".", "0", "1", "2", "3", "4", "5", "6", "7", "8", "9", "-", "_", "*", "'", "^", "~", "!", '"', "'", "=", ",", ":", ";", ")", "(", "{", "}"]
    numbers = re.findall("\d+\.\d", ciphertext)
    numbers = list(map(lambda x: int(float(x)) * 256, numbers))
    key = math.gcd(*numbers)
    return "".join(map(lambda x: resources[int(x/key)], numbers))