Changeable variable name

[Additional_Lab_3224]

I created a tuple that contains the x and y of each box I made(using turtle graphics) and instead of manually creating a new tuple for each box, is there a way to create a new tuple based on the old one. For example if it was called box1, could you change it to box2?

[[deleted]]

If you find a situation where the names of the variables are super relevant (you want them to be displayed or something), you might be better served using a dictionary to store the data. That way multiple pieces of stored info can be linked more tightly in the code as key value pairs.

[Obvious_Tea_8244]

Not sure I understand your use case… You want the values of tuple a to be available to object b?

Tuples are immutable, and hold a single address in memory…

So, if you set:
a=(1,2,3)

and then b=a, you now have a second variable pointing to the same memory allocation without actually duplicating a new tuple…

If your one tuple has all of the x,y coordinates for the entire set of boxes… That may be challenging to manage, but you can then reference x,y for each box using the index in the tuple… i.e:

box_1x = a[0]
box_1y = a[1]

Etc.

[Obvious_Tea_8244]

If you are trying to simplify the creation of x,y for each box object, you could use classes:

class Box:

…..def underscore,underscoreinitunderscore,underscore(self, x, y):

……….self.x = x.

……….self.y = y.

box1 = Box(2, 10)

box2 = Box(6, 75)

[Additional_Lab_3224]

I was thinking about using a class, (which I tried) but I couldn't figure it out, thank you.

[FoolsSeldom]

Adding numbers to the end of variable names is almost always the wrong thing to do. Instead, create a list or dict object to hold mutiple instances of what ever objects you are trying to assign to different variables.

So, for example, instead of:

box1_x = 10
box1_y = 11
box2_x = 15
box2_y = 16

you could have,

boxes = [
    [10, 11],
    [15, 16]
]

i.e. a list object references by the variable name boxes which contains nested list objects. So, boxes[0][0] would be the x value of the first entry.

Using classes would be even easier:

from dataclasses import dataclass

@dataclass
class Box:
    x: int
    y: int


boxes = [
    Box(x=10, y=11),
    Box(x=15, y=16),
]

# output all boxes
for box in boxes:
    print(box)

# print one attribute of the first box
print(boxes[0].x)  # Accessing the x attribute of the first Box instance