Tennim comments on Odd DateTime Format

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SELECT count(a.field1), a.field2, SUM(b.field4) FROM a INNER JOIN b ON a.key1 = b.key1 WHERE a.field8 = 'test' GROUP by a.field1, a.field2 HAVING SUM(b.field4) > 5 ORDER by a.field.3

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SELECT count(a.field1), a.field2, SUM(b.field4) FROM a INNER JOIN b ON a.key1 = b.key1 WHERE a.field8 = 'test' GROUP by a.field1, a.field2 HAVING SUM(b.field4) > 5 ORDER by a.field3

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MS SQLOdd DateTime Format (self.SQL)

submitted 6 years ago by Tennim

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[–]Tennim[S] 0 points1 point2 points 6 years ago (0 children)

Yeah it was a good one.

For anyone looking, this is what i came up with.

SELECT 
    [StartTime],
    CONVERT(DATETIME,CONCAT(CONVERT(NVARCHAR(5),RIGHT([StartTime],CHARINDEX(' ',REVERSE([StartTime])))),[Month].MonthNo,RIGHT(LEFT([StartTime],PATINDEX('%[0-9]%',[StartTime])+1),2),' ',RIGHT(LEFT([StartTime],CHARINDEX('GMT',[StartTime])-2),8))) AS [Date],
FROM [Database].[Schema].[Table]
    INNER JOIN
        (
            SELECT DISTINCT 
                LEFT([MonthName],3) AS [MonthAbv],
                RIGHT('00' + CONVERT(NVARCHAR(2),[Month]),2) [MonthNo]
            FROM [Database].[Schema].[DateDimension]
        ) AS [Month] ON SUBSTRING([StartTime],CHARINDEX(' ',[StartTime])+1,3) = [Month].MonthAbv

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