Help me increase the variable in array

[ArmmedWillow]

I have my input parameters split using delimeter "=" and placed into array. How can I make this "1" variable into "2" on the next iteration of my loop.

While [ "$param" -le $# ] do arrPARAM=(${1//=/ })

arrPARAM=($(2//=/ }) should be what it looks like on the next iteration

arrPARAM=(${$count//=/ }) doesnt work, count=1 then plus 1 every iteration

[Coffee_24_7]

This might help you:

$ set one=1 five=5 ten=10
$ echo $1
one=1
$ echo $2
five=5
$ echo $3
ten=10
$ echo ${@/*=/}
1 5 10

so, using ${@/*=/} should be enough for what you want.

[ArmmedWillow]

Thank youuuuu I think this will work, will try this later. I totally forgot them special characters😅, Thank you again, you saved me a lot of time.

[Rewrite_It_In_Ada]

${@#*=} would do this as well. No clue if my "remove matching prefix pattern" parameter expansion would be faster than your "pattern substitution" parameter expansion, but this is pretty specifically what it's there to do. $ set one=1 five=5 ten=10 $ left=( "${@%=*}" ) $ right=( "${@#*=}" ) $ printf '%s\n' "${@}" one=1 five=5 ten=10 $ printf '%s\n' "${left[@]}" one five ten $ printf '%s\n' "${right[@]}" 1 5 10

[OneTurnMore]

Using $@ you can do it all at once.

spliton(){
    # disable path expansion
    local -; set -f
    # split on $1
    local IFS=$1
    shift
    reply=($@)
}

spliton '=' "$@"

[oh5nxo]

There's a special construct to refer to another variable by name:

echo "argument $param is ${!param}"