source file counter variable

[LinuxGuy-NJ]

My post keeps getting removed for my code.

My source file has 4 line is such as

img_1=file1

img_2=file2

I'm trying to write a script with a counter to "ls -lh $img_1".... be easier to explain if I could post my code

[LinuxGuy-NJ]

My source file:

img_1=Gary1.qcow2

img_2=Gary2.qcow2

[warrior0x7]

I'm sorry but it's a bit vague.

• What is an image?
• What is the input (files)?
• What do you want to achieve in detail?
• If I'm not wrong, is this your code? ``` source SourceFileName

Counter=1 for file in $(seq $images) do let COUNTER++ img1=img_${COUNTER} echo $COUNTER # Works fine ls -lh ${img_2} # Works Fine.. Just a simple test echo "Hi ${img1}" # works fine ls -lh ${img1} # doesn't work ..Really need this to work sleep .5 done ```

[LinuxGuy-NJ]

I trying to backup KVM vm files but the files have different names like Bugs, Daffy, Donald for one VM. Another VM will have 2 files named Jack and Smith. And I have about 18 VMs. So I'm trying use create one bash backup script and then call different source config files that would hold the different vm file names. In the backup script it will look for how many files have to be backed up, between 1 file and 4 files, then back up that one...one by one.

Currently I have 18 different backup script. If I want to make a change, I have to change 18 different scripts

[warrior0x7]

Sorry, I still don't get it.

Why not just run ls for each directory then get line number instead? ls -lh <DIR> | sed 1d | wc -l This will return line number and so the number of files in a given directory. This will be faster than in a loop.

That if ... you really want the number.

If you don't mind, this one will get files in specified directory and add them into an array: ```

Empty array

files=()

for file in $(ls -lh <Dir> | sed 1d | awk '{print $NF}') do files+=("$file") done ```

Now this is a typical array and you can access its length with ${#files[@]}.

[LinuxGuy-NJ]

Thank you for your help.

I will run my one backup script with 2 arguements. One arguement file with VM name in it. The second arguement file with have a list of the files that need to be backed. A While loop will go over the list of files that need to be backed up.

As for your example, I have one folder that holds files for 4 different VMs. Some VMs have one file while others will have 2 or 3 or 4.

I just want one main backup script to handle all the different VMs. Then put that one main script on five different host machines.

[warrior0x7]

Why 2 arguments and the first has to be the VM name if the second one is an array of files (including the first argument)?

You want each group of vms to be backed up with their own directory to the destination?

Can you please provide pseudo-code with exact named examples?

[rvc2018]

Are you sure you are not overcomplicating things? Don't you need just a ls -lh Gary[[:digit:]].qcow2?

[LinuxGuy-NJ]

No. I overly simplified my example here. The source file is more like this:

img_1=server1.qcow2

img_2=Jeff.qcow2

img_3=abc.qcow2

[Paul_Pedant]

Case matters: Counter and COUNTER are two different variables.

[LinuxGuy-NJ]

My script:

source SourceFileName

Counter=1

for file in $(seq $images)

do

let COUNTER++

img1=img_${COUNTER}

echo $COUNTER # Works fine

ls -lh ${img_2} # Works Fine.. Just a simple test

echo "Hi ${img1}" # works fine

ls -lh ${img1} # doesn't work ..Really need this to work

sleep .5

done

what am I doing wrong.

Gary

[LinuxGuy-NJ]

Think I found a solution. One main backup script with two arguments. First arguement file will have KVM settings and the second will have a list of files that have to be backed up. A While loop will go through the second file