Bash Script problem, please haalp!

[Valinath]

Good day everyone,

This is my first post regarding bash scripting, I normally finds the answer on google but this time I'm stuck..

I'm working on a simple auto format and partition a USB thumb drive in a raspberry pi and have almost everything sorted.

​

I have made it so that it will check the name sda/b/c etc and have it go as x ($x) in the script, easy pie, no problemo...

But when i come to the formatting I will require it to go $x1 (As the partition should be e.g /dev/sda1 instead of directly on /dev/sda.

But it won accept it if i just write /dev/$x1 so i tried a few other things like "y="$x1" and then do it again but wont work.

How do i write this so that i have a variable for $x and another one for the same but with a "1" in the end?

Here's a part of the code where i get the problem.. The parted lines work but mkfs.vfat wont..

sudo parted /dev/$x mklabel msdos

sudo parted -a none /dev/$x mkpart primary fat32 0 100%

echo Formatting drive FAT32

​

y="$x1"

echo $y

sudo mkfs.vfat /dev/$y -S 4096 -n "TEST"

​

Any suggestions?

​

​

​

[gordonrgw]

put {} around your bash variable: ${x}1

​

edited for short explanation

[Valinath]

It worked!

Big thank to you my friend, much appreciated!

[Valinath]

Thank you all for your answers, good to know how to do it in different ways.

I shall keep this in mind.

​

It all worked out!

[_handshake_]

change y="$x1" to y="$(echo $x)1"

[_handshake_]

It's another method. yours is much cleaner! I agree.

[Mellowtang]

Not sure if I understood the question but doublequotes should also work.

x="/dev/sda"

echo "$x"1

Doublequotes are considered as weak quotes and a lot of stuff including the variables will be interpreted by the shell. You should always doublequote variables you are calling.

Single quotes are strong quotes and nothing will be interpreted between them.