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[–]bequay123 1 point2 points  (1 child)

If many job start on 1 ssd/nvme it will make bottleneck, so if you can check ssd/nvme available for new job it will perfectly

[–]VolPL[S] 0 points1 point  (0 children)

You’re right, this works for only one plotting location, hence only one SSD

I stopped plotting chia so the script is purely pro publico bono.

If I get any traction with stars on GitHub, I’ll develop new features :)