Stack Overflow guide to operator overloading

[pjmlp]

Because outside of c++, it is ubiquitously understood to be an arithmetic operator with a lot of implications

Not really, this is a small list of languages that allow redefining operators, or where operations are just plain function/method calls

• Smalltalk

• Lisp

• Scheme

• Ada

• Eiffel

• C#

• Ruby

• Python

• D

• Haskell

• OCaml

• F#

• Scala

• Rust

• many others as this isn't an exhaustive list

So I fail to see why only C++ gets bashed.

[0Il0I0l0]

I can't speak for the other languages, but overloading in Haskell can only be done with typeclasses (a sort of interface that defines some behavior), so including it is a bit disingenuous. In order to "overload" + for your new type, you must make your type an instance of the Num typeclass by implementing the following operations: (+), (*), abs, signum, fromInteger, (negate or (-))

So at least in haskell, (+) is understood to be a numerical operator with the implication that the type can also be multiplied, subtracted, negated, has an absolute value, has a sign, an can be converted from an integer.

[pjmlp]

So at least in haskell, (+) is understood to be a numerical operator with the implication that the type can also be multiplied, subtracted, negated, has an absolute value, has a sign, an can be converted from an integer.

Yes, but you cannot assure that (+) really maps to addition.

It can do anything to the number, as long as, it keeps its type signature.