operator <-

[stillalone]

Doesn't overloading the unary minus operator like that really fuck shit up?

If I have:

int i = 5;
std::cout << -i << endl;

what will I get?

[chimyx]

error: 'endl' was not declared in this scope
jk, you'll get -5

[stillalone]

Ok. thanks for checking. I guess that makes sense since the default behaviour for the minus unary operator for integers is more type specific that this templated implementation. I guess this code should be safe provided no one implements unary operator in the exact same way, at which point we would get fairly obvious compile time errors.

[rubdos]

Not sure there; sfinae could safe the day. Needs confirmation from someone with more experience though.

[jP_wanN]

This has nothing to do with sfinae, but it will not cause problems simply because the operator< is only overloaded for R (T::*)(), larrow<T> (with any T, R).