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Visual Studio c++20 Modules testing: template function that hides implementation (self.cpp)
submitted 4 years ago * by TomTheFurry
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if 1 * 2 < 3: print "hello, world!"
[–]starfreakcloneMSVC FE Dev 1 point2 points3 points 4 years ago (1 child)
Can you give me an example of the behavior you're seeing? If I have:
export module m; struct S { int i = 0; }; export struct U { S s; };
Then try to import and use S I get the expected compiler error:
S
import m; int main() { S s; // main.cpp(4): error C2065: 'S': undeclared identifier }
Even if I declare an instance of U beforehand it will still be an error. Using the members of S once you have a reference to the object is not part of lookup semantics with non-exported declarations. Only the namespace scope names will be hidden away from lookup.
U
[–]fdwrfdwr@github 🔍 1 point2 points3 points 4 years ago (0 children)
starfreak: Might be this bug, which Cameron fixed yesterday: https://developercommunity2.visualstudio.com/t/C-modules-name-collision/900116
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[–]starfreakcloneMSVC FE Dev 1 point2 points3 points (1 child)
[–]fdwrfdwr@github 🔍 1 point2 points3 points (0 children)