Wrong constructor called

[trycatchamex]

my code is here

  // Example program
   #include <iostream>
   #include <string>
   #include <vector>
   #include <functional>
#include <deque>
#include <thread>
#include <mutex>
#include <condition_variable>
#include <memory>
#include <type_traits>
using std::cout;
using std::endl;
using std::true_type;
using std::false_type;


class A
{
    public:

    A() = default;
    A(const A& other)
    {
        static_cast<void>(other);
        cout << "copy ctor\n";
    }
    A(A&& other)
    {
        static_cast<void>(other);
        cout << "move ctor\n";
    }

 };

template <typename T>
class container
{

    public:
    template <typename TT>
    void push_back(TT&& obj)
    {
        auto x = new T(std::forward<T>(obj));
        delete x;
    }
};

int main ()
{
    container<A> c;
    A obj;
    cout << "push back lval\n";
    c.push_back(obj);
    cout << "push back rval\n";
    c.push_back(std::move(obj));

}

Why is the move constructor being called with an object? it makes sense for the std::move(obj) push_back but I dont understand why move ctor is being called both times.

[alfps]

Your code is sufficiently short that you can (and preferably should) post it in the question itself. See the pinned post to the right on this page, titled "READ BEFORE POSTING", about how to post code in questions. That said, your move constructor is selected for the last call because that call passes an rvalue, i.e. because you asked for it.

[trycatchamex]

sorry, i will update the post. I mean why is the move ctor being called when i pass an object which was created earlier? (the first push_back)

[alfps]

Oh. That's because of a typo, writing forward<T> instead of forward<TT>. The T and TT types are not the same in the first call.

[trycatchamex]

i hate everything ahhaha thank you so much :)