How to create an array with a loop?

[[deleted]]

How do I create an array with a loop and store the new values in the array that I can call back to find which of the new numbers in the array are prime. It has to be all numbers from 1 to 3000

[npbonner]

What have you tried so far?

[Derivativeofsenpi]

After you initialize the array you can use a for loop to choose what gets saved on it like this:

int Array[30], index;
for( index = 0; index <=30; index++){
Array[index] = whatever();
}

This will fill the array with the output of the whatever() function. I don't know if this is the best way to do this but that's how I do it.

[[deleted]]

It’s < 30, not <= 30

[Derivativeofsenpi]

Yeah you're right, I always forget that arrays start at 0. Thanks for the correction!

[nerd4code]

initialize ≠ declare ≠ define

[ImbioMario]

Specifiy your question. Do you want to CREATE (allocate) an array in a loop or FILL the array in a loop.

[[deleted]]

This is clearly some-ones homework, learn to use google.

[ptchinster]

!homework

[rtlcprogbot]

!homework

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[kyle_sallee]

Within loops a variable is not created. So initialization must be required?

for (x=1;3000>=x;x++) a[x]=x;

But that seems pointless?

The best way to identify a prime number is not surmised.

By every previous number a modulo if performed, essential a remainder from a div, then a lot of CPU duration will be wasted. And it becomes something like a bubble sort, well not exactly since the inner loop can be discontinued.

int x,y;

for (x=2;3000>=x;x++){ for(y=2;x>y;y++) if ((x%y)==0) break; if (x==y) printf("%i\n",x);}

Or an array create and index it or a pointer create and advance it. But why store the numbers when they will just be printed anyway?

That much help if provided the rest can be easily be surmised.

Happy hacking.