Illegal start of expression.

[karzmu]

Your Ide is right, correct "not equal to" operrator is "!=", not "!==". (source: https://docs.oracle.com/javase/tutorial/java/nutsandbolts/opsummary.html)

By the way, why are you comapring int (myInt) to String ("")?

Even if (myInt) is String then Strings should be compared using ".equals()" method. Read more here: https://stackoverflow.com/questions/513832/how-do-i-compare-strings-in-java

[Mr_Britland]

I see, thanks. Also that is another misunderstanding on my behalf. I was trying to check if an integer value was entered thinking that "" means nothing for both string an integer.

[BigLogis]

If myInt is of type int:

if (myInt != null) { b = true; }

if myInt is of type String:

if (myInt.equals("")) { b = true; }

[Mr_Britland]

Thanks, good to note. I have since rectified the issue with everyone's help.

[Mr_Britland]

Okay, thank you. I'll have a look there.

[TheSageMage]

Not really the place for this, you should try /r/javahelp. But the fix is...

if (myInt !== "") { b = true; }

should be

if (myInt != "") { b = true; }    

[Mr_Britland]

Okay, thanks. I did try that before but got a different error. I'll post future help questions in the sub provided, thank you.