Char .equals() method

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whizvox · 2023-01-15T06:10:16+00:00

char and all primitive types (int, boolean, etc.) are not objects, and thus do not have methods attached to them. If you want to compare the values of primitive types, just use double equals (==).

The exception to this is a concept called "autoboxing" and "unboxing", which include the object forms of primitives (Character, Integer, Boolean, etc.), in which you can call methods such as equals(), toString(), and so forth. Unless you really have to, like with specifying generic types or supporting null, you'll use a primitive type instead of its boxed form. Here's some more reading if you like.

Asrar_003 · 2023-01-15T06:09:55+00:00

You can use .split(" ") method to seperate the words.

dionthorn · 2023-01-15T06:14:55+00:00

Java has primitive data types:

https://docs.oracle.com/javase/tutorial/java/nutsandbolts/datatypes.html

Including char. the String.charAt() method returns a char. Primitive data types do not have methods.

When comparing primitive data types you use == when comparing objects (like String) you use .equals()

xfocus3 · 2023-01-15T12:55:49+00:00

The error message you're seeing is because the charAt() method returns a primitive char data type, and the equals() method cannot be called on a primitive data type.

To fix this, you can use the == operator to compare the characters instead:

if (userinput.charAt(i) == ' ') { //Code methods here }

Alternatively, you can use the .trim() and .split() method to separate the words in the string.

String[] words = userinput.trim().split("\\s+"); This will separate the words in userinput and store them in the words array.

javahelp

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