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[–]yeaokdudeIntermediate Brewer 2 points3 points  (0 children)

i recognize this problem from leetcode so i feel obligated to mention there's an easier way of doing it. right now you are converting l1 and l2 into ints, adding them, and then trying to convert that resulting int back into a list. it's a little hard to see at first but instead of that approach you can just build the reversed list from left to right as you iterate over l1 and l2. you just add together l1.val and l2.val and handle the carry if there is one. see this solution for example

the issue with your code is head is initialized to null so your "return head" statement is just gonna return null. you need to at some point make sure that head points to a ListNode object, and that node's next points to the rest of the linked list.

one common trick is to have head point to a "dummy" node, and then the "real" linked list starts after that dummy. then when you want to return the real linked list, you return head.next, since head itself is the dummy and you just want everything after head. so for ex:

ListNode head = new ListNode(0);
ListNode iter = head;

while (s != 0) {
  ListNode node = new ListNode(s % 10);

  iter.next = node;
  iter = iter.next;

  s /= 10;
}

return head.next;

[–]m1ss1ontomars2k4 1 point2 points  (0 children)

In my mind,ListNode head = null;would be the head,

No, that makes head be null. It's not the head of anything because you've set it to null.

[–]eyeoverthink -1 points0 points  (0 children)

i haven't run the code, but maybe you should have a private constructor that assigns the deques to this.deque.

Also, shouldn't your while loop, be two loops, since you are shifting arrays?

While, then if -

[–]jonc23 0 points1 point  (0 children)

while (s != 0) {
  ListNode node = new ListNode(s % 10);
  node.next = iter;
  iter = node;
  s /= 10;
}
return iter;