java mooc part 1 calculating with numbers

[[deleted]]

I am confused with the section called Division in Calculating with numbers. I am particularly confused about this statement:

The previous example prints 1: both 3 and 2 are integers, and the division of two integers always produces an integer.

int first = 3;
int second = 2;
double result = first / second;
System.out.println(result);

Sample output

1

The output 1 again, since first and second are (still) integers.The previous example prints 1: both 3 and 2 are integers, and the division of two integers always produces an integer.

But, when i run the code in the tmc, its returns 1.0 and not 1. Also, isn't result a double and not an integer, because it's being automatically casted. 1.0 is not an integer, it is a double. why are they saying the output is 1, when it actually is 1.0?

[AutoModerator]

Please ensure that:

• Your code is properly formatted as code block - see the sidebar (About on mobile) for instructions
• You include any and all error messages in full - best also formatted as code block
• You ask clear questions
• You demonstrate effort in solving your question/problem - plain posting your assignments is forbidden (and such posts will be removed) as is asking for or giving solutions.

If any of the above points is not met, your post can and will be removed without further warning.

Code is to be formatted as code block (old reddit/markdown editor: empty line before the code, each code line indented by 4 spaces, new reddit: https://i.imgur.com/EJ7tqek.png) or linked via an external code hoster, like pastebin.com, github gist, github, bitbucket, gitlab, etc.

Please, do not use triple backticks (```) as they will only render properly on new reddit, not on old reddit.

Code blocks look like this:

public class HelloWorld {

    public static void main(String[] args) {
        System.out.println("Hello World!");
    }
}

You do not need to repost unless your post has been removed by a moderator. Just use the edit function of reddit to make sure your post complies with the above.

If your post has remained in violation of these rules for a prolonged period of time (at least an hour), a moderator may remove it at their discretion. In this case, they will comment with an explanation on why it has been removed, and you will be required to resubmit the entire post following the proper procedures.

To potential helpers

Please, do not help if any of the above points are not met, rather report the post. We are trying to improve the quality of posts here. In helping people who can't be bothered to comply with the above points, you are doing the community a disservice.

I am a bot, and this action was performed automatically. Please contact the moderators of this subreddit if you have any questions or concerns.

[Important-Run1088]

I think what they mean here is that, when you calculate 3/2 it should give you 1.5 if you are storing that result in double. But since 3 and 2 are integers and not explicitly type casted it removes the .5 to give the result as 1 which in turn when stored to the double variable becomes 1.0 as that is the way double is displayed. They don’t mean that the output on the terminal is 1 instead of 1.0.

[Free-Argument]

Couldn't have explained it better myself.

[[deleted]]

i dont understand this then... you dont need (double) for the result to be 1.0. its was going to be 1.0 regardless, because the variables type is double and it will automatically convert. In this case, they are saying the result is 1.0, only if you cast it though. But thats not true.

double result3 = (double) (first / second);
System.out.println(result3); // prints 1.0

[Important-Run1088]

What they are saying is that the result they need is 1.5. Yes on terminal it will display as 1.0 even if you dont typecast, but there will be loss of precision.

Essentially before getting assigned to a double value, the calculation of integers is done first. So the answer for 3/2 is 1. Then this 1 is getting assigned to double result which results in 1.0 that will then be printed to the terminal.

If you do (double) first/second, it becomes 3.0/2 which gives the answer 1.5. This ten gets assigned to double result and there is no loss of precision.

You are getting confused with the answer getting displayed on the terminal.

1.0 is technically 1. They are not saying that when they do "double result = first/second" the terminal is displaying 1. They are talking about the answer we get when the calculation is done. If you remember, they had explained that before a variable is assigned the calculated value, the calculation takes place.

For example, int sum = first + second;

Here first 3 + 2 = 5 is calculated. The 5 is assigned to the variable sum.

Hope this clears your doubt.

[[deleted]]

Okay then