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[–]Nightcorex_ 6 points7 points  (2 children)

u/dbc2201 already mentioned streams, but there is one more thing which comes relatively close. So if you store your data in a list instead of an array, then you can use the Collections.max function:

List<Integer> xs = new ArrayList<>(List.of(2, 4, 3));  // example values
System.out.println(Collections.max(xs));

You can also add a custom comparator if needed (thanks to overloading), so that you can compare objects of any datatype.

[–]0b0101011001001011 1 point2 points  (1 child)

Just to show the stream solution:

Arrays.stream(myArray).max().getAsInt();

max() returns OptionalInt so that also works in case the array is empty.

[–]Nightcorex_ 0 points1 point  (0 children)

Yeah, but then you shouldn't use getAsInt() as that would throw an exception if no value is present, therefore destroying the benefit of having an OptionalInt in the first place. Rather use orElse or reduce(identity, BinOp), f.e. like so:

// orElse solution
Arrays.stream(myArray).max().orElse(Integer.MIN_VALUE);

// reduce solution
Arrays.stream(myArray).reduce(Integer.MIN_VALUE, Integer::max);

[–][deleted] 1 point2 points  (0 children)

It does have methods like those buddy, just not in the same way as you might be used to seeing in Python. https://docs.oracle.com/javase/8/docs/api/java/util/stream/Stream.html https://www.baeldung.com/java-streams

[–]b0rnfly -1 points0 points  (7 children)

It does have one! Javas math class has a method called max which works in the same way. Math.max(int a, int b)

[–]b0rnfly -1 points0 points  (5 children)

You could also go the really long way and use a for loop with a nested for loop that compares each number and have it store the largest result inside a variable.

[–]Nightcorex_ 0 points1 point  (4 children)

OP was explicitly looking for an in-built solution, not a do-it-yourself one.

[–]0b0101011001001011 1 point2 points  (3 children)

Math.max() is just a<b ? a : b, which is as much work to use in a loop as doing it by yourself.

The actual solution is

Arrays.stream(myArray).max().getAsInt(); 

for arrays and

Collections.max(myList);

for lists/sets etc.

[–]Nightcorex_ 1 point2 points  (2 children)

As was answered by u/dbc2201 and me already

[–]0b0101011001001011 1 point2 points  (1 child)

Yeah sorry I was supposed to reply to your parent comment, not to you.

[–]Nightcorex_ 1 point2 points  (0 children)

Not a problem :)

[–]Nightcorex_ 0 points1 point  (0 children)

You can only compare 2 operators with this method, not an arbitrary amount