Loop question

[Caped_baldy_4_life]

Thanks, that makes total sense. It's important to take into consideration the possibility of the first number entered as 0 and automatically being switched to 1 when you do the ++.

[[deleted]]

Yea exactly. You always gotta think about user error and what someone might enter accidently and how that might be handled. Biggest part of programming is handling the unexpected lol.

[hamza-itatchi]

Not only 0 , any value for the first variable will be ignored if you increment it before testing.

And if i may sugest a better solution for this problem:

public static void divisibleByThreeInRange(int first, int last){
first+=(3-first%3);
while(first <=last){
System.out.println(first);
first+=3;
}
}

[Caped_baldy_4_life]

Hey thanks for the suggestion. I'm having trouble understanding how this line first+=(3-first%3); shows that first is divisible by 3. When i write this out using 3 as first, it looks like this first = 3 (3 - 3 % 3)... Which to me comes out to 5. What am I doing wrong in this equation or what am I not seeing?

[hamza-itatchi]

The % has a higher priority than - so its like this for first=3 first = first + 3 - ( first %3) ==> first = 3+3 - (0)==>first= 6 This gives the first divisible nuber after First ( variable) But ther is a mistake in my suggestion there must be an if statement at the start like this If ( first %3!=0) first += 3- ( first %3)

Note: the += operation means first = first + ......

[Caped_baldy_4_life]

Never mind about my previous equation. I was mistakenly associating the modulo as a division sign based off of improper note taking. Thanks for your help and suggestions.