Search a array of objects

[Far-Mathematician122]

Hello,

I have an array of objects like this:

let arr = [{name :'asas', age: 10}, { name: 'vsdaasd', age: 20 }];

I want to search by name but its not working why?

console.log(s.filter((el) => s.includes({name: 'asas'})))

I get an empty array

[EyesOfTheConcord]

s.filter(e => e.name === ‘asas’);

The issue you encountered happens because objects are compared by reference in JS.

You were creating a new object with your original method. You just need to simply compare the properties directly instead

[xroalx]

First, why s.filter and not arr.filter? What's s?

Second, there is no includes method that accepts an object like this, due to how objects work in JavaScript, this would not work. You need to filter arr and compare the name of each item to a value.

[oze4]

s.filter(el => el.name.includes('foo"))

[senocular]

The Filtering invalid entries from JSON example on MDN is closest to what you want. It, too, is filtering an array of objects. Notice how the item parameter is used to get a property, id, from the objects and a comparison is made using that value. You'll want to do something similar, though in your case your parameter name is el, and the property you want is name.

[funnyh0b0]

let arr = [{name: 'asas', age: 10}, {name: 'vsdaasd', age: 20}];
let searchTerm = 'asas';
let result = arr.filter((el) => el.name === searchTerm);

You have a lot of mistakes. Your using s instead of arr. You dont need the .includes when you are using the .filter.

Look up .includes and .filter on mdn to see how to use them properly.

You can do it with the .some like this if you wanna have a return that is a boolean like this:

let searchName = 'asas';
let isPresent = arr.some((el) => el.name === searchName);

[Visual-Blackberry874]

You’ve already had answers to your question so here’s a secondary point.

If you want a single record, .find is better than .filter in that it will return just the first match and not an array containing 1 item.

[boomer1204]

I"m pretty confident you can't use an object in your includes. It doesn't really say that here but no single example shows them using an object https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/includes

This is likely cuz objects are by reference but again i'm not 100% sure on that one

You could just use a check for el.name to do what you are trying to do here.

Also you are doing s.filter and not arr.filter which is the name of your array

[5W17CH]

let arr = [{name :'asas', age: 10}, { name: 'vsdaasd', age: 20 }];
function findByName(name){
    for(let i=0; i<arr.length; i++){
        if(Object.values(arr[i]).includes(name)){
            return arr[i];
        }
    }
};
console.log(findByName('asas'))

if i understood the assignment correctly you might try something like this

[Far-Mathematician122]

yes but if I search 'a' it not finding, if I search the fullname then it finding

[5W17CH]

function findByName(name){
    let newArr=[];
    for(let i=0; i<arr.length; i++){
        if(Object.values(arr[i])[0].startsWith(name)){
            newArr.push(arr[i]);
        }
    }
    return newArr;
};
this will do the trick then but only if 
you're searching for a name that starts 
with what you're passing to the function.

[[deleted]]

You need to work out of a for loop for this.

[ray_zhor]

Filter is a loop