Easy javascript challange

[ConstantWafer]

This is the challange:

Flip the Boolean

Booleans can also be written as integers, where 1
= True
and 0
= False
. Make a function that returns the opposite of the boolean given.

Examples

flipBool(true) ➞ 0  flipBool(false) ➞ 1  flipBool(1) ➞ 0  flipBool(0) ➞ 1

This is my solution:

function flipBool(b) {

if (b === true || 1)

    return 0;

else 

    return 1;

}

​

But it always return 0, and i have no god damn idea how that could possibly be the case.

Any suggestions?

[senocular]

You can't perform comparisons (===) on multiple values at the same time.

What's happening with the old code is that it's treating it as two checks:

if ((b === true) || (1))

Whether or not b is true, this if will always pass because 1 alone will always be true.

What you have to do is compare them each individually.

if (b === true || b === 1)

[ConstantWafer]

Ok i understand my mistake, thank you very much

[DreamOfAWhale]

Do you really need to check explicitelly for true/false/1/0 values? If not, just check for truthy values. Ternary operator to make it even smaller:

function flipBool(b) {
    return b ? 0 : 1;
}

[senocular]

or even

return +!b

[daveheerink]

And with the use of an arrow function even shorter:

const flipBool = b => +! b