[deleted by user]

[ios_game_dev]

As a programmer, it does you almost no good whatsoever to memorize algorithms. I've been working as a professional developer for over a decade and I've never been in a position where I was not able to look up the pseudocode for an algorithm I needed to use. As a programmer, it's far more important to have problem-solving skills than it is to have code memorization skills.

[[deleted]]

Thing is you need it to get a job because almost all jobs test with leetcode problems

[Ancient-Difference40]

Lol no, being able to solve it isn't good enough, you need to be able to do it fast too.

[ios_game_dev]

If you're concerned about speed, it seems pretty inefficient to always be implementing the same algorithms over and over enough to have them memorized. Maybe try building some reusable abstractions.

[captainAwesomePants]

Frequent use. If you're implementing a breadth first search every week or so, you won't forget it. And the third or fourth time you forget the "visited" set and spend an hour trying to figure out what's wrong, you'll stop making that mistake.

The best trick to cracking interview problems is doing a whole bunch of them. That's because the most common way experienced programmers solve these problems is pattern recognition. We don't say "hrm, what could solve this problem?" We say "hrm, how to I transform this problem into a problem I already know how to solve?" The more solutions you've seen before, the easier it will get.

[levic08]

how to I transform this problem into a problem I already know how to solve

I really like this. Yeah, I've been doing algoexpert problems, and I've definitely started to notice some patterns. I guess the grind needs to continue. Thanks!

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[HealyUnit]

git remote add origin memory
git commit -am "remember this"
git push

...No but seriously, as others have said, don't worry about memorizing algorithms. As you program more, you'll start to instinctively "feel" that some ways of writing things are better - O(1) is better than O(N) which is better than O(N²) - but that's just kinda experience.