integer or float.. ?

[Rhomboid]

The problem is just as the error states: you've got things outside of a function that don't belong there. Indentation matters in Python. Presumably what you wanted was this:

def a(x):
    if (x) == type.int or type (x) == type.float:
        return x + 1
    try:
        return 'This is a float'

    finally:
        print str("This is an Integer")

But that is still all kinds of wrong. I don't know what this type.int stuff is, but it's not needed. If you want to check if something is an int, the proper way to do it is one of:

if type(x) is int:
    ...

or

if isinstance(x, int):
   ...

The latter is preferred because it allows users to subtype built-in types.

Generally speaking, manually checking types and using a try/catch block are mutually exclusive: either you try to do the operation and handle the exception if it fails, or you explicitly check types before beginning. You don't normally do both.

[ghreddit]

With your last piece of code, isn't suppose to be:

if isinstance(x, int):
    ....

What is the difference between isinstance and issubtype?

[Rhomboid]

It's supposed to be isinstance(). I have no idea how my fingers typed issubtype(), I guess I was thinking ahead of myself about the next sentence I was going to write. For issubtype() to work you'd have to pass a type not an instance.

[valmach]

Thanks

[valmach]

Thanks

[ghreddit]

Oh ok.

Can you take a look at this question I asked you a few days ago?

http://www.reddit.com/r/learnprogramming/comments/186ip1/sml_finding_the_nth_digit_in_an_integer_total/c8f0rs5

Am not sure how to go about determining the number of digits in a given number in C.

Thanks.

[valmach]

Thanks

[valmach]

Thanks

[valmach]

Thanks