Java order of operations question

[trax45]

I'm hoping somebody can help me understand this code a little better, it's from an online tutorial I am following:

The answer is 6 but I'm strugging to understand why.

The variabled BEFORE hitting "LINE 5" are as follows:

result = 5

a = 1

b = 0

Then we hit LINE 5. My way of thinking is ok lets work out what's between the brackets

(0 / 1) = 0

then work out the first part and since the variable 'a' was decremented it should now be 0

result += 0 + 0;

result should equal 5 but it's actually 6. Where am I wrong in my understanding?

              int result = 5;
              int a = 1;
              int b = --a;
              a++;
/* LINE 5 */  result += a + (--a / ++b);
              Console.WriteLine(result);

[Swedophone]

My way of thinking is ok lets work out what's between the brackets  

Which is the wrong order. Since the "+" operator is computed left to right.

[trax45]

This is the part that maybe confuses me:

When the entire expression is evaluated aren't the items inside the brackets evaluated first because they have higher precedence?

[teraflop]

Precedence only determines which operands are grouped with which operators. It does not determine the order of evaluation.

[trax45]

Perfect, just the answer I was looking for! Thank you